The resistors of resistances 2 Ω, 4 Ω and 8 Ω are connected in parallel, then the…
Physics · JEE Main · NTA Exams — Current Electricity
The resistors of resistances 2 Ω, 4 Ω and 8 Ω are connected in parallel, then the equivalent resistance of the combination will be:
- \(\frac{8}{7} n\)
- \(\frac{7}{8} n\)
- \(\frac{7}{4} n\)
- \(\frac{4}{9} n\)
Answer
(A) 8 7 n
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