The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the…
Mathematics · JEE Main · NTA Exams — Statistics and Probability
The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probability of 2 successes is
- \(\frac{37}{265}\)
- \(\frac{219}{256}\)
- \(\frac{128}{256}\)
- \(\frac{28}{256}\)
Answer
(D) 28 256
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