x 1 , x 2 , x 3 , ...... x 50 are fifty numbers such that x r r + 1 for r = 1, 2, 3…
Mathematics · JEE Main · NTA Exams — Statistics and Probability
x1, x2, x3, ...... x50 are fifty numbers such that xr < xr + 1 for
r = 1, 2, 3, ...., 49 . Five numbers out of these are picked up at random. The probability that the five numbers have x20 as the middle number is
r = 1, 2, 3, ...., 49 . Five numbers out of these are picked up at random. The probability that the five numbers have x20 as the middle number is
- \(\frac{{ }^{20} \mathrm{C}_{2} \times{ }^{30} \mathrm{C}_{2}}{{ }^{50} \mathrm{C}_{2}}\)
- \(\frac{{ }^{30} \mathrm{C}_{2} \times{ }^{19} \mathrm{C}_{2}}{{ }^{50} \mathrm{C}_{5}}\)
- \(\frac{{ }^{19} \mathrm{C}_{2} \times{ }^{31} \mathrm{C}_{3}}{{ }^{50} \mathrm{C}_{5}}\)
- none the these
Answer
(B) ^ 30 C _ 2 ^ 19 C _ 2 ^ 50 C _ 5
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