_ x 2 1+ 2+x - 3 x-2
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\(\lim _{x \rightarrow 2} \frac{\sqrt{1+\sqrt{2+x}}-\sqrt{3}}{x-2}\)
- \(\frac{1}{8 \sqrt{3}}\)
- \(\frac{1}{\sqrt{3}}\)
- \(8 \sqrt{3}\)
- \(\sqrt{3}\)
Answer
(A) 1 8 3
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