Consider the function f (x) = max x 2 , (1 – x) 2 , 2x (1 – x) where 0 ≤ x ≤ 1 . Let RMVT…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Consider the function f (x) = max {x2, (1 – x)2, 2x (1 – x)}
where 0 ≤ x ≤ 1 .
Let RMVT is applicable for f (x) on (a, b) then a + b + c is
(where c is point such that f ´ ( c) = 0)
- \(\frac{2}{3}\)
- \(\frac{1}{3}\)
- \(\frac{1}{2}\)
- \(\frac{3}{2}\)
Answer
(D) 3 2
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