A steady current is set up in a cubic network composed of wires of equal resistance and…
Physics · JEE Main · NTA Exams — Magnetic Effects of Current and Magnetism
A steady current is set up in a cubic network composed of wires of equal resistance and length d as shown in figure. What is the magnetic field at the centre P due to the cubic network ?
- \(\frac{0}{4 \pi} \cdot \frac{2 \mathrm{I}}{\mathrm{~d}}\)
- \(\frac{0}{4 \pi} \cdot \frac{3 \mathrm{I}}{\sqrt{2} \mathrm{~d}}\)
- 0
- \(\frac{0}{4 \pi} \cdot \frac{8 \pi \mathrm{I}}{\mathrm{~d}}\)
Answer
(C) 0
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