When 0.15 kg of ice of 0°C mixed with 0.30 kg of water at 50°C in a container, the…
Physics · JEE Advanced · NTA Exams — Thermodynamics
When 0.15 kg of ice of 0°C mixed with 0.30 kg of water at 50°C in a container, the resulting temperature is 6.7°C. Calculate the heat of fusion of ice.
(swater = 4186 J kg–1 K–1)
(swater = 4186 J kg–1 K–1)
- 3.34 × 105 J kg–1 k–1
- 3.63 × 105 J kg–1 k–1
- 3.34 × 106 J kg–1 k–1
- 4.19 × 105 J kg–1 k–1
Answer
(A) 3.34 × 10 5 J kg –1 k –1
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