For the reaction A + 2B ⇌ C, the expression for equilibrium constant is
Chemistry · JEE Main · NTA Exams — Equilibrium
For the reaction A + 2B \(\text { ⇌ }\) C, the expression for equilibrium constant is
- \(\frac{[\mathrm{A}][\mathrm{B}]^{2}}{[\mathrm{C}]}\)
- \(\frac{[\mathrm{A}][\mathrm{B}]}{[\mathrm{C}]}\)
- \(\frac{[\mathrm{C}]}{[\mathrm{A}][\mathrm{B}]^{2}}\)
- \(\frac{[\mathrm{C}]}{2[\mathrm{~B}][\mathrm{A}]}\)
Answer
(C) [ C ] [ A ][ B ]^ 2
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