The rate constant for forward and backward reactions of hydrolysis of ester are 1.1 × 10…
Chemistry · JEE Main · NTA Exams — Equilibrium
The rate constant for forward and backward reactions of hydrolysis of ester are 1.1 × 10–2 and 1.5 × 10–3 per minute respectively. Equilibrium constant for the reaction is
CH3COOC2H5 + H2O \(\text { ⇌ }\)CH3COOH + C2H5OH
CH3COOC2H5 + H2O \(\text { ⇌ }\)CH3COOH + C2H5OH
- 4.33
- 5.33
- 6.33
- 7.33
Answer
(D) 7.33
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- In which of the following dissociation of NH 4 OH will be minimum
- The solubility product of A 2 X 3 is 1.08 × 10 -23 . Its solubility will be:
- For a weak acid HA, Ostwald’s dilution law is represented by the equation
- The exothermic formation of ClF 3 is represented by the equation Cl 2 (g) + 3F 2 (g) ⇌ 2ClF 3 (g); ∆H = – 329…
- Consider the following statements The pH of a mixture containing 400 mL of 0.1 M H 2 SO 4 and 400 mL of 0.1 M…
- Two buffer solutions, A and B, each made with acetic acid and sodium acetate differ in their pH by one unit…
- Calculate the partial pressure of carbon monoxide from the following CaCO 3 (s) CaO(s) + CO 2 ↑; K p = 8 × 10…
- In a chemical reaction, A +2 ~B K C + D , the initial concentration of B was 1.5 times of the concentration…