The solubility product of A 2 X 3 is 1.08 × 10 -23 . Its solubility will be:
Chemistry · JEE Main · NTA Exams — Equilibrium
The solubility product of A2X3 is 1.08 × 10-23. Its solubility will be:
- \(1 \times 10^{-3}\)
- \(1 \times 10^{-5}\)
- \(1 \times 10^{-4}\)
- \(1 \times 10^{-5}\)
Answer
(B) 1 10^ -5
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