Two identical thin uniform rods of mass m and length L are placed as shown in figure. The…
Physics · JEE Advanced · NTA Exams — Gravitation
Two identical thin uniform rods of mass m and length L are placed as shown in figure. The gravitational interaction force between the two rods is
\(1 \rightleftarrows L \longrightarrow 1 \leftarrow L \longrightarrow 1 \leftarrow L \longrightarrow\)
\(1 \rightleftarrows L \longrightarrow 1 \leftarrow L \longrightarrow 1 \leftarrow L \longrightarrow\)
- \(\frac{G m^{2}}{4 L^{2}}\)
- \(\frac{G m^{2}}{2 L^{2}}\)
- \(\frac{G m^{2}}{9 L^{2}}\)
- \(\frac{G m^{2}}{L^{2}} \ell n\left(\frac{4}{3}\right)\)
Answer
(D) G m^ 2 L^ 2 n ( 4 3 )
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