The escape velocity for a body projected vertically upwards from the surface of the earth…
Physics · JEE Advanced · NTA Exams — Gravitation
The escape velocity for a body projected vertically upwards from the surface of the earth is 11.2 km s-1. If the body is projected in a direction making an angle 45° with the vertical, the escape velocity will be:
- \(\frac{11.2}{\sqrt{2}} \mathrm{kms}^{-1}\)
- \(11.2 \times \sqrt{2} \mathrm{kms}^{-1}\)
- 11.2 × 2 km s-1
- 11.2 km s-1
Answer
(D) 11.2 km s -1
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