The binding energy of deutron is 2.2 MeV and that of 2 He 4 is 28 MeV. If two deutrons…
Physics · JEE Main · NTA Exams — Atoms and Nuclei
The binding energy of deutron is 2.2 MeV and that of 2He4 is 28 MeV. If two deutrons are fused to form one 2He4, then the energy released is
- 19.2 MeV
- 23.6 MeV
- 25.8 MeV
- 30.2 MeV
Answer
(B) 23.6 MeV
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If radius of the _ 13 ^ 27 Al nucleus is estimated to be 3.6 fermi, then the radius of _ 52 ^ 125 Te nucleus…
- On bombarding U 235 by slow neutrons, 200 MeV energy is released. If the power output of atomic reactor is…
- Which one of the following graphs represents correctly the variation of photoelectric current (i) with…
- Hydrogen ( 1 H 1 ), Deuterium ( 1 H 2 ), singly ionised Helium ( 2 He 4 ) + and doubly ionised lithium ( 3 Li…
- Radioactive element decays to form a stable nuclide, then the rate of decay of reactant ( dN dt ) will vary…
- In the nuclear reaction, _ 1 ^ 2 H + _ 1 ^ 2 H 1 2 He + 1 n n , if the binding energy of deuteron is 2.23 MeV…
- If the radius of 150 is 3 fermi then what is the radius of Pb _ 12 ^ 255 (in fermi)
- If an electron has, orbital angular momentum quantum number l = 7, then it will have an orbital angular…
More Atoms and Nuclei questions · Browse all practice questions