Radioactive element decays to form a stable nuclide, then the rate of decay of reactant (…

Physics · JEE Main · NTA ExamsAtoms and Nuclei

Radioactive element decays to form a stable nuclide, then the rate of decay of reactant \(\left(\frac{\mathrm{dN}}{\mathrm{dt}}\right)\) will vary with time (t) as shown in figure

Answer

(C)

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