Two rods 1 and 2 are released from rest as shown in figure. Given: l 1 = 4 l , m 1 = 2m…
Physics · JEE Advanced · NTA Exams — Rotational Motion
Two rods 1 and 2 are released from rest as shown in figure.
Given: l1 = 4l, m1 = 2m, l2 = 2l and m2 = m.
There is no friction between the two rods. If a be the angular
acceleration of rod 1 just after the rods are released. Then:
What is the normal reaction between the two rods at this instant?
- \(16 \sqrt{3} m \ell \alpha\)
- \(\frac{4 m \ell \alpha}{\sqrt{3}}\)
- \(\frac{32 m l a}{3 \sqrt{3}}\)
- \(12 \sqrt{3} m \ell \alpha\)
Answer
(C) 32 m l a 3 3
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