If roots x 1 and x 2 of x 2 + 1 = x a satisfy | x _ 1 ^ 2 - x _ 2 ^ 2 |> 1 a , then a (…
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
If roots x1 and x2 of x2 + 1 = \(\frac{\mathrm{x}}{\mathrm{a}}\) satisfy
\(\left|\mathrm{x}_{1}^{2}-\mathrm{x}_{2}^{2}\right|>\frac{1}{\mathrm{a}},\) then \(\mathrm{a} \in\left(-\frac{1}{\sqrt{\mathrm{k}}}, 0\right) \cup\left(0, \frac{1}{\sqrt{\mathrm{k}}}\right)\)
the numerical quantity k must be equal to
\(\left|\mathrm{x}_{1}^{2}-\mathrm{x}_{2}^{2}\right|>\frac{1}{\mathrm{a}},\) then \(\mathrm{a} \in\left(-\frac{1}{\sqrt{\mathrm{k}}}, 0\right) \cup\left(0, \frac{1}{\sqrt{\mathrm{k}}}\right)\)
the numerical quantity k must be equal to
- \(k = 3\)
- \(k = 4\)
- \(k = 5\)
- \(k = 6\)
Answer
(C) k = 5
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