The expression for displacement of an object in SHM is x = A cos (ωt). The potential…
Physics · JEE Main · NTA Exams — Oscillations and Waves
The expression for displacement of an object in SHM is x = A cos (ωt). The potential energy at \(t=\frac{T}{2}\) is (take potential energy at mean position to be zero):
- \(\frac{1}{2} k A^{2}\)
- \(\frac{1}{8} k A^{2}\)
- \(\frac{1}{4} k A^{2}\)
- zero
Answer
(A) 1 2 k A^ 2
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