When two sound waves with a phased difference of / 2 , and each having amplitude A and…
Physics · JEE Main · NTA Exams — Oscillations and Waves
When two sound waves with a phased difference of \(\pi / 2\), and each having amplitude A and frequency \(\boldsymbol{\beta}\)are superimposed on each other, then the maximum amplitude and frequency of resultant wave are
- \(\frac{A}{\sqrt{2}}: \frac{\omega}{2}\)
- \(\frac{A}{\sqrt{2}}: \omega\)
- \(\sqrt{2} A: \frac{\omega}{2}\)
- \(\sqrt{2} A: \omega\)
Answer
(D) 2 A:
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