The path difference between the two waves y_ 1 =a_ 1 ( t- 2 x ) and y_ 2 =a_ 2 ( t- 2 x +…
Physics · JEE Main · NTA Exams — Oscillations and Waves
The path difference between the two waves \(y_{1}=a_{1} \sin \left(\omega t-\frac{2 \pi x}{\lambda}\right)\) and \(y_{2}=a_{2} \cos \left(\omega t-\frac{2 \pi x}{\lambda}+\phi\right)\) is
- \(\frac{\lambda}{2 \pi} \phi\)
- \(\frac{\lambda}{2 \pi}\left(\phi+\frac{\pi}{2}\right)\)
- \(\frac{2 \pi}{\lambda}\left(\phi-\frac{\pi}{2}\right)\)
- \(\frac{2 \pi}{\lambda}(\phi)\)
Answer
(B) 2 ( + 2 )
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