0.2 molar solution of formic acid is ionized 3.2%. Its ionization constant is
Chemistry · JEE Main · NTA Exams — Equilibrium
0.2 molar solution of formic acid is ionized 3.2%. Its ionization constant is
- 9.6 × 10–3
- 2.1 × 10–4
- 1.25 × 10–6
- 4.8 × 10–5
Answer
(B) 2.1 × 10 –4
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- For the given hypothetical reactions, the equilibrium constants are as follows: X ⇌ Y; K 1 = 1.0 Y ⇌ Z; K 2 =…
- The rate of forward reaction is two times that of reverse reaction at a given temperature and identical…
- In which of the following acid-base titration, pH is greater than 8 at the equivalence point ?
- For the reaction 2SO 2 + O 2 ⇌ 2SO 3 , the units of K c are
- In a reaction A + B ⇌ C + D, the concentrations of A, B, C and D (in moles/litre) are 0.5, 0.8, 0.4 and 1.0…
- Equilibrium constant (K p ) for the reaction N _ 2 O _ 4 ( ~g ) 2 NO _ 2 ( ~g ) is 0.25 atm, if the partial…
- Solution of 0.1 N NH 4 OH and 0.1 N NH 4 Cl has pH 9.25, then find out the pK b of NH 4 OH.
- Consider the reaction equilibrium, 2SO 2 (g) + O 2 (g) ⇌ 2SO 3 (g) ΔH o = -198K On the basis of…