Equilibrium constant (K p ) for the reaction N _ 2 O _ 4 ( ~g ) 2 NO _ 2 ( ~g ) is 0.25…
Chemistry · JEE Main · NTA Exams — Equilibrium
Equilibrium constant (Kp) for the reaction \(\mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_{2}(\mathrm{~g})\) is 0.25 atm, if the partial pressure of N2O4 is increased from 1 atm to 2 atm then the Kp for the above reaction will become:
- 0.5 atm
- 0.25 atm
- 0.0625 atm
- will depend on degree of dissociation of N2O4
Answer
(B) 0.25 atm
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