The pH value of 0.1 M solution of anilinium chloride is: ( K _ a of C _ 5 H _ 5 NH _ 3 ^…
Chemistry · JEE Main · NTA Exams — Equilibrium
The pH value of 0.1 M solution of anilinium chloride is:
\(\left(\mathrm{K}_{\mathrm{a}} \text { of } \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}_{3}^{+}=10^{-5}\right)\)
- 3.5
- 3
- 4.5
- none
Answer
(A) 3.5
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