Given array l Co ^ 3+ + e ^ - Co ^ 2+ ; E ^ =+1.81 ~V ~Pb ^ 4+ +2 e ^ - Pb ^ 2+ ; E ^ =+1.67 ~V Ce ^ 4+ + e ^ - Ce ^ 3+ ; E ^ =+1.61 ~V Bi ^ 3+ +3 e ^ - Bi ^ ; E ^ =+0.20 ~V array Oxidizing power of the species will increase in the order:

Given array l Co ^ 3+ + e ^ - Co ^ 2+ ; E ^ =+1.81 ~V ~Pb ^ 4+ +2 e ^ - Pb ^ 2+ ; E ^…

Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry

Given

\[\begin{array}{l} \mathrm{Co}^{3+}+\mathrm{e}^{-} \longrightarrow \mathrm{Co}^{2+} ; \mathrm{E}^{\prime \prime}=+1.81 \mathrm{~V} \\ \mathrm{~Pb}^{4+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Pb}^{2+} ; \mathrm{E}^{\prime \prime}=+1.67 \mathrm{~V} \\ \mathrm{Ce}^{4+}+\mathrm{e}^{-} \longrightarrow \mathrm{Ce}^{3+} ; \mathrm{E}^{\prime \prime}=+1.61 \mathrm{~V} \\ \mathrm{Bi}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Bi}^{\prime} ; \mathrm{E}^{\prime \prime}=+0.20 \mathrm{~V} \end{array}\]

Oxidizing power of the species will increase in the order:

Co³⁺ < Ce⁴⁺ < Bi³⁺ < Pb⁴⁺
Co³⁺ < Pb⁴⁺ < Ce⁴⁺ < Bi²⁺
Ce⁴⁺ < Pb⁴⁺ < Bi³⁺ < Co³⁺
Bi³⁺ < Ce⁴⁺ < Pb⁴⁺ < Co³⁺

Answer

(D) Bi 3+ < Ce 4+ < Pb 4+ < Co 3+

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Given array l Co ^ 3+ + e ^ - Co ^ 2+ ; E ^ =+1.81 ~V ~Pb ^ 4+ +2 e ^ - Pb ^ 2+ ; E ^…

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