A parabolic bowl with its bottom at origin has the shape y= x^ 2 20 . Here, x and y are…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A parabolic bowl with its bottom at origin has the shape \(y=\frac{x^{2}}{20}\). Here, x and y are in metres. The maximum height at which a small mass m can be placed on the bowl without slipping (coefficient of static friction is 0.5) is:


- 2.5 m
- 1.25 m
- 1.0 m
- 4.0 m
Answer
(B) 1.25 m
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- You are supplied with three identical rods of same length and mass. The length of each rod is 2π. Two of them…
- Two particles of mass m each are tied at the ends of a light string of length 2 a . The whole system is kept…
- Two blocks m 1 and m 2 are pulled on a smooth horizontal surface, and are joined together with a spring of…
- Three identical blocks are suspended on two identical springs one below the other as shown in figure. If…
- A block of mass m is pushed towards a movable wedge of mass nm and height h, with a velocity u. All surfaces…
- Three masses of 1 kg, 6 kg and 3 kg are connected to each other with threads and are placed on a table as…
- A motor cycle and a car are moving on a horizontal road with the same velocity. If they are brought to rest…
- A cannon ball is fired with a velocity 200 m/s at an angle of 60° with the horizontal. At the highest point…
More Laws of Motion questions · Browse all practice questions