If a _ 1 be the roots of x ^ 2 - a ( x -1)+ b = 0 , then the value of 1 a^ 2 -a a^ 2 + 1…

Mathematics · JEE Main · NTA ExamsComplex Numbers and Quadratic Equations

If \(\mathrm{a}_{1} \beta\) be the roots of  \(\mathbf{x}^{2}-\mathbf{a}(\mathbf{x}-1)+\mathbf{b}=\mathbf{0}\), then the value of  \(\frac{1}{a^{2}-a a^{2}}+\frac{1}{\beta^{2}-a \beta}+\frac{2}{a+b}\)  is
  1. \(\frac{4}{a+b}\)
  2. \(\frac{1}{a+b}\)
  3. \(0\)
  4. \(-1\)

Answer

(A) 4 a+b

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