If y= [x+ 1+x^ 2 ]^ n , then [1+x^ 2 ] d^ 2 y d x^ 2 +x d y d x is
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\(\text { If } y=\left[x+\sqrt{1+x^{2}}\right]^{n} \text {, then }\left[1+x^{2}\right] \frac{d^{2} y}{d x^{2}}+x \frac{d y}{d x} \text { is }\)
- n2y
- -n2y
- -y
- 2x2y
Answer
(A) n 2 y
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