5^ x +(2 3 )^ 2 x -169 0 is true in the interval.
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
\(5^{x}+(2 \sqrt{3})^{2 x}-169 \leq 0\) is true in the interval.
- (–∞, 2)
- (0, 2)
- (2, ∞)
- (0, 4)
Answer
(A) (– ∞ , 2), (B) (0, 2)
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