The angular frequency of the damped oscillator is given by, = ( k m - r^ 2 4 m^ 2 ) where…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
The angular frequency of the damped oscillator is given by, \(\omega=\sqrt{\left(\frac{k}{m}-\frac{r^{2}}{4 m^{2}}\right)}\) where k is the spring constant, m is the mass of the oscillator and r is the damping constant. If the ratio \(\frac{r^{2}}{m k}\) is 8%, the change in time period compared to the undamped oscillator is approximately as follows:
- increases by 8%
- decreases by 8%
- increases by 1%
- decrease by 1%
Answer
(C) increases by 1%
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