Two simple harmonic motions are represented by the equations y_ 1 =0.1 (100 t+ 3 ) and y_…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
Two simple harmonic motions are represented by the equations \(y_{1}=0.1 \sin \left(100 \pi t+\frac{\pi}{3}\right)\) and
\(y_{2}=0.1 \cos \pi t\). The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is
\(y_{2}=0.1 \cos \pi t\). The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is
- \(\frac{-\pi}{3}\)
- \(\frac{\pi}{6}\)
- \(\frac{-\pi}{6}\)
- \(\frac{\pi}{3}\)
Answer
(C) - 6
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