A horizontal rod of mass m and length L is pivoted smoothly at one end. The rod’s other…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
A horizontal rod of mass m and length L is pivoted smoothly at one end. The rod’s other end is supported by a spring of force constant k. The rod is rotated (in vertical plane) by a small angle θ from its horizontal equilibrium position and released. The angular frequency of the subsequent simple harmonic motion is
- \(\sqrt{\frac{3 k}{m}}\)
- \(\sqrt{\frac{k}{3 m}}\)
- \(\sqrt{\frac{3 k}{m}+\frac{3 g}{2 L}}\)
- \(\sqrt{\frac{k}{m}}\)
Answer
(A) 3 k m
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