A wave equation which gives the displacement along Y-direction is given by y=10^ -4 [ (60…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
A wave equation which gives the displacement along Y-direction is given by
\(y=10^{-4}[\sin (60 t+20 x)]\)
where x and y are in metres and t is time in seconds. This represents a wave
\(y=10^{-4}[\sin (60 t+20 x)]\)
where x and y are in metres and t is time in seconds. This represents a wave
- travelling with a velocity of 30 m/s in the negative x-direction
- of wavelength metres
- of frequency 30/ Hertz
- of amplitude 10–4 m travelling along the negative x-direction.
Answer
(C) of frequency 30/ Hertz, (D) of amplitude 10–4 m travelling along the negative x-direction.
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