The potential at a point x (measured in µm) due to some charges situated on the x-axis is…
Physics · JEE Main · NTA Exams — Electrostatics
The potential at a point x (measured in µm) due to some charges situated on the x-axis is given by :
V (x) = 20/(x2 – 4) volt
The electric field E at x = 4µm is given by
V (x) = 20/(x2 – 4) volt
The electric field E at x = 4µm is given by
- \(\frac{5}{3} \mathrm{~V} / \mu \mathrm{m}\) and in the –ve x direction
- \(\frac{5}{3} \mathrm{~V} / \mu \mathrm{m}\) and in the +ve x direction
- \(\frac{10}{9} \mathrm{~V} / \mu \mathrm{m}\) and the –ve x direction
- \(\frac{10}{9} \mathrm{~V} / \mu \mathrm{m}\) and in the +ve x direction
Answer
(D) 10 9 ~V / m and in the +ve x direction
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