The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 A…
Chemistry · JEE Main · NTA Exams — Atomic Structure
The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 \(\text { A }\). The wavelength of the second spectral line in the Balmer series of singly-ionized helium atom is
- 1215 \(\text { A }\)
- 1640 \(\text { A }\)
- 2430 \(\text { A }\)
- 4687 \(\text { A }\)
Answer
(A) 1215 A
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The difference in wavelength of second and third lines of Balmer series in the atomic spectrum is
- When electrons in N shell of excited hydrogen atom return to ground state, the number of possible lines…
- The ionization energy of H atom is 13.6 eV. The ionization energy of Li 2+ ion will be
- Given below are two statements: Statement I: The orbitals having same energy are called as degenerate…
- The increasing order (lowest first) for the values of e m ( charge mass ) for electron (e), proton (p)…
- Given below are two statements. One is labelled as Assertion and the other is labelled as Reason. Assertion…
- The ratio of the difference in energy between the first and the second Bohr orbit to that between second and…
- Mass of neutron is .............. times the mass of electron.
More Atomic Structure questions · Browse all practice questions