A particle is moving along a circular path of radius 3 meter in such a way that the…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A particle is moving along a circular path of radius 3 meter in such a way that the distance travelled measured along the circumference is given by
S = \(\frac{t^{2}}{2}+\frac{t^{3}}{3}\). The accelration of particle when t = 2 sec is-
S = \(\frac{t^{2}}{2}+\frac{t^{3}}{3}\). The accelration of particle when t = 2 sec is-
- 1.3 m/s2
- 13 m/s2
- 3 m/s2
- 10 m/s2
Answer
(B) 13 m/s 2
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