A uniform ball of radius r rolls without slipping down from the top of a sphere of radius…

Physics · JEE Advanced · NTA ExamsRotational Motion

A uniform ball of radius r rolls without slipping down from the top of a sphere of radius R. The angular velocity of the ball when it breaks from the sphere is
  1. \(\sqrt{\frac{5 g(R+r)}{17 r^{2}}}\)
  2. \(\sqrt{\frac{\log (R+r)}{17 r^{2}}}\)
  3. \(\sqrt{\frac{5 g(R-r)}{10 r^{2}}}\)
  4. \(\sqrt{\frac{\log (R+r)}{7 r^{2}}}\)

Answer

(B) (R+r) 17 r^ 2

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Rotational Motion questions · Browse all practice questions