The wave function ( ) of 2s is given by _ 2 s = 1 2 2 ( 1 a_ 0 )^ 1 2 (2- r a_ 0 ) e^ - r…

Chemistry · JEE Main · NTA ExamsAtomic Structure

The wave function \((\Psi)\) of 2s is given by
 \(\Psi_{2 s}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_{0}}\right)^{\frac{1}{2}}\left(2-\frac{r}{a_{0}}\right) e^{-\frac{r}{2 a_{0}}}\)
 At \(r=r_{0}\), radial node is formed. Thus, \(F_{0}\) in terms of \(a_{0}\) (Jee Main 2023)
  1. \(r_{0}=a_{0}\)
  2. \(r_{0}=4 a_{0}\)
  3. r0 = \(\frac{a_{0}}{2}\)
  4. \(r_{0}=2 a_{0}\)

Answer

(D) r_ 0 =2 a_ 0

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Atomic Structure questions · Browse all practice questions