The wave function ( ) of 2s is given by _ 2 s = 1 2 2 ( 1 a_ 0 )^ 1 2 (2- r a_ 0 ) e^ - r…
Chemistry · JEE Main · NTA Exams — Atomic Structure
The wave function \((\Psi)\) of 2s is given by
\(\Psi_{2 s}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_{0}}\right)^{\frac{1}{2}}\left(2-\frac{r}{a_{0}}\right) e^{-\frac{r}{2 a_{0}}}\)
At \(r=r_{0}\), radial node is formed. Thus, \(F_{0}\) in terms of \(a_{0}\) (Jee Main 2023)
\(\Psi_{2 s}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_{0}}\right)^{\frac{1}{2}}\left(2-\frac{r}{a_{0}}\right) e^{-\frac{r}{2 a_{0}}}\)
At \(r=r_{0}\), radial node is formed. Thus, \(F_{0}\) in terms of \(a_{0}\) (Jee Main 2023)
- \(r_{0}=a_{0}\)
- \(r_{0}=4 a_{0}\)
- r0 = \(\frac{a_{0}}{2}\)
- \(r_{0}=2 a_{0}\)
Answer
(D) r_ 0 =2 a_ 0
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