The maximum integral part of positive value of a for which, the least value of 4x 2 – 4 a…

Mathematics · JEE Advanced · NTA ExamsComplex Numbers and Quadratic Equations

The maximum integral part of positive value of a for which, the least value of 4x2 – 4ax + a2 – 2a + 2 on [0, 2] is 3, is
  1. \(5\)
  2. \(6\)
  3. \(8\)
  4. \(9\)

Answer

(C) 8

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