For a ∈ R (the set of all real numbers), a ≠ –1, _ n (1^ a +2^ a + +n^ a ) (n+1)^ a-1 [(n…
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
For a ∈ R (the set of all real numbers), a ≠ –1, \(\lim _{n \rightarrow \infty} \frac{\left(1^{a}+2^{a}+\ldots+n^{a}\right)}{(n+1)^{a-1}[(n a+1)+(n a+2)+\ldots+(n a+n)]}=\frac{1}{60} .\)
Then a =
Then a =
- 5
- 7
Answer
(B) 7
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