A wave traveling in positive X- direction with A = 0.2 m has a velocity of 360 m/s. If λ…
Physics · NEET · NTA Exams — Oscillations and Waves
A wave traveling in positive X- direction with A = 0.2 m has a velocity of 360 m/s. If λ = 60 m the correct expression for the wave is
- \(\lambda=0.2 \sin \left[2 \pi\left(6 t+\frac{x}{60}\right)\right]\)
- \(y=0.2 \sin \left[\pi\left(6 t+\frac{x}{60}\right)\right]\)
- \(y=0.2 \sin \left[2 \pi\left(6 t-\frac{x}{60}\right)\right]\)
- \(y=0.2 \sin \left[\pi\left(6 t-\frac{x}{60}\right)\right]\)
Answer
(C) y=0.2 [2 (6 t- x 60 ) ]
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