Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on…
Chemistry · Class 12 · CBSE — Solutions
Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on dissolving 1 g of Y in 20 g of liquid X. If molar mass of X is 200, what is the molar mass of Y?
- 20
- 50
- 100
- 200
Answer
(A) 20
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