A parallel plate capacitor is charged to V volt by a battery. The battery is disconnected…
Physics · Class 12 · CBSE — Electrostatic Potential & Capacitance
A parallel plate capacitor is charged to V volt by a battery. The battery is disconnected and the separation between the plates is halved. The new potential difference across the capacitor will be
- \(\frac{\mathrm{V}}{2}\)
- V
- 2V
- \(\frac{\mathrm{V}}{4}\)
Answer
(A) V 2
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