A parallel plate capacitor of area A, plate separation d and capacitance C is filled with…

Physics · Class 12 · CBSEElectrostatic Potential & Capacitance

A parallel plate capacitor of area A, plate separation d and capacitance C is filled with four dielectric materials having dielectric constants \(\kappa_1\) , \(\kappa_2\) , \(\kappa_3\) and \(\kappa_4\) as shown in the figure below. If a single dielectric material is to be used to have the same capacitance C in this capacitor, then its dielectric constant \(\kappa\) is given by:

  1. \(\frac{2}{\kappa }=\frac{3}{\kappa _{1}+\kappa _{2}+\kappa _{3}}+\frac{1}{\kappa _{4}}\)
  2. \(\frac{1}{\kappa}=\frac{1}{\kappa_{1}}+\frac{1}{\kappa_{2}}+\frac{1}{\kappa_{3}}+\frac{3}{2 \kappa_{4}}\)
  3. \(\kappa=\kappa_{1}+\kappa_{2}+\kappa_{3}+3 \kappa_{4}\)
  4. \(\kappa=\frac{2}{3}\left(\kappa_{1}+\kappa_{2}+\kappa_{3}\right)+2 \kappa_{4}\)

Answer

(A) 2 = 3 _ 1 + _ 2 + _ 3 + 1 _ 4

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