A block of mass m is pulled along a horizontal surface by applying a force at an angle θ…
Physics · JEE Main · NTA Exams — Work, Energy and Power
A block of mass m is pulled along a horizontal surface by applying a force at an angle θ with the horizontal. If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is μ, then the work done by the applied force is
- \(\frac{\mu m g d}{\cos \theta+\mu \sin \theta}\)
- \(\frac{\mu m g d \cos \theta}{\cos \theta+\mu \sin \theta}\)
- \(\frac{\mu m g d \sin \theta}{\cos \theta+\mu \sin \theta}\)
- \(\frac{\mu m g d \cos \theta}{\cos \theta-\mu \sin \theta}\)
Answer
(B) m g d +
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