The compound that will react most readily with NaOH to form methanol is (2001)
Chemistry · JEE Advanced · NTA Exams — Alcohols, Phenols and Ethers
The compound that will react most readily with NaOH to form methanol is (2001)
- \(\left(\mathrm{CH}_{3}\right)_{4} \mathrm{~N}^{\oplus} \mathrm{I}^{\ominus}\)
- CH3OCH3
- \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~S}^{\oplus} \mathrm{I}^{\ominus}\)
- (CH3)3CI
Answer
(A) ( CH _ 3 )_ 4 ~N ^ I ^
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