The value of ( _ n=1 ^ 50 ^ -1 ( 1 1+n+n^ 2 ) ) is

Mathematics · JEE Main · NTA ExamsSets, Relations and Functions

The value of \(\cot \left(\sum_{n=1}^{50} \tan ^{-1}\left(\frac{1}{1+n+n^{2}}\right)\right)\) is

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(A)

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