A source, approaching with speed u towards the open end of a stationary pipe of length L…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
A source, approaching with speed u towards the open end of a stationary pipe of length L, is emitting a sound of frequency fs. The farther end of the pipe is closed. The speed of sound in air is v and f0 is the fundamental frequency of the pipe. For which of the following combination(s) of u and fs, will the sound reaching the pipe lead to a resonance?
- u = 0.8v and fs = f0
- u = 0.8v and fs = 2f0
- u = 0.8v and fs = 0.5f0
- u = 0.5v and fs = 1.5f0
Answer
(B) u = 0.8 v and f s = 2 f 0
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- An open pipe is suddenly closed at one end with the result that the frequency of third harmonic of the closed…
- A particle executes simple harmonic motion between x = –A and x = +A . The time taken for it to go from 0 to…
- A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the…
- A block with mass M is connected by a massless spring with stiffness constant k to a rigid wall and moves…
- A car sounding its horn at 480 Hz moves towards a high wall at a speed of 20 m/s. If the speed of sound is…
- A whistle giving out 450 Hz approaches a stationary observer at a speed of 33 m/s. The frequency heard by the…
- A particle is vibrating in a simple harmonic motion with amplitude 4 cm. At what distance from the…
- An air column in a pipe, which is closed at one end, will be in resonance with a vibrating tuning fork of…
More Oscillations and Waves questions · Browse all practice questions