A particle executes simple harmonic motion between x = –A and x = +A . The time taken for…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
A particle executes simple harmonic motion between
x = –A and x = +A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then
x = –A and x = +A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then
- T1 < T2
- T1 > T2
- T1 = T2
- T1 = 2T2.
Answer
(A) T 1 T 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- An organ pipe closed at one end is excited to support the third overtone. It is found that air in the pipe has
- The friction coefficient between two blocks of masses 1 kg and 4 kg shown in figure is μ and the horizontal…
- Two stretched strings of same material are vibrating under the same tension in fundamental mode. The ratio of…
- A long string having a cross-sectional area 0.80 mm 2 and density 12.5 g/cm 3 is subjected to a tension of 64…
- One end of a spring of force constant k is fixed to a vertical wall and the other to a body of mass m resting…
- Two pulses in a stretched string whose centres are initially 8 cm apart are moving towards each other as…
- A siren placed at a railway platform is emitting sound of frequency 5 kHz. A passenger sitting in a moving…
- Transverse waves are produced in a long string by attaching its free end to a vibrating tuning fork. Figure…
More Oscillations and Waves questions · Browse all practice questions