In a triangle ABC, 2ca sin ( A - B + C 2 ) is equal to
Mathematics · JEE Main · NTA Exams — Trigonometry
In a triangle ABC, 2ca sin \(\left(\frac{\mathrm{A}-\mathrm{B}+\mathrm{C}}{2}\right)\)is equal to
- a2 + b2 – c2
- c2 + a2 – b2
- b2 – c2 – a2
- c2 – a2 – b2
Answer
(B) c 2 + a 2 – b 2
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