In circular motion, the centripetal acceleration is given by-
Physics · JEE Main · NTA Exams — Rotational Motion
In circular motion, the centripetal acceleration is given by-
- \(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{r}}\)
- \(\vec{\omega} \times \vec{v}\)
- \(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{v}}\)
- \(\vec{\omega} \times \overrightarrow{\mathrm{r}}\)
Answer
(B) v
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