In the above question, tension force at midpoint of the rope is

Physics · JEE Main · NTA Exams — Laws of Motion

1. \(\frac{F(M+m / 2)}{M+m}\)
2. \(\frac{F M / 2}{M+m}\)
3. \(\frac{F m / 2}{M+m}\)
4. none

Answer

(A) F(M+m / 2) M+m

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